From 200mg of co2 10 21 molecules are removed
WebSep 16, 2024 · weight of CO₂ = 200mg = 200 × 10⁻³ g = 0.2g molecular weight of CO₂ = 44g/mol ∴number of mole of CO₂ = 0.2/44 Now, number of molecules = number of moles × 6.023 × 10²³ = 0.2/44 × 6.023 × 10²³ = 0.027 × 10²³ = 2.7 × 10²¹ A/C to question, 10²¹ molecule are removed from 2.7 × 10²¹ molecules of CO₂. WebIf 10 21 molecules are removed from 200 mg of CO 2, the number of moles of CO 2 left is : A 2.88×10 −3 B 28.8×10 −3 C 0.288×10 −3 D 1.66×10 −3 Hard Solution Verified by Toppr Correct option is A) Answer: …
From 200mg of co2 10 21 molecules are removed
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WebThe correct option is A 2.88×10−3 mol. 1 mole of CO2 has a mass of 44 g and contains N A number of molecules. So, 1021 molecules will be present in = 44×1021 6.023×1023 = … WebNov 11, 2015 · If 10 21 molecules of CO 2 are removed from 200mg of CO 2 sample, what is the number of moles of CO 2 left? Share with your friends. Share 0 ... (6,02 x 10^23 molecules CO2 / 1 mole CO2) = 2.74 x 10^21 molecules CO2 So if you take away 1 x 10^21 molecules, you have left 2.74 x 10^21 - 1.0 x 10^21 = 1.74 x 10^21 molecules …
WebNov 1, 2012 · From 200 mg of CO 2 ,10 21 molecules are removed.How many moles of CO 2 are left ? a) 0.288 b) 2.88 c) 0.00288 d) 0.0288 Share with your friends 29 Follow 10 Certified by MeritNation Expert Abhinav Verma, Meritnation Expert added an answer, on 2/11/12 Molar mass of CO2 = 44 g Given mass = 200 mg = 0.2 g No. of moles = 0.2 / 44 … WebApr 18, 2013 · From 200mg of carbon dioxide, 10 to the power 21 molecules are removed. How many frams and moles of carbon dioxide are left? Asked by Prince …
WebNo. of moles in 200 mg= 1000×44200 =4.54×10 −3moles So now, No. of moles in 10 21 molecules = 6.02×10 2310 21 =1.67×10 −3moles Now to get the number of moles left when 10 21 moles are removed from the 200g or 4.54×10 −3moles, following calculation is done: No. of moles left =(4.54−1.67)×10 −3=2.88×10 −3 mol Was this answer helpful? 0 0 H WebFrom 200 mg of CO 2 when x molecules are removed. 2.89×10 −3 moles of CO 2 are left x will be A 10 20 molecules B 10 10 molecules C 21 molecules D 10 21 molecules Medium Solution Verified by Toppr Correct option is D) Molar Mass of CO 2=44 g Given mass =200 mg=0.2 g Number of moles = 440.2= 2201 =4.54×10 −3
WebFrom 320 mg of O 2,6.023×10 20 molecules are removed, the no. of moles remained are: A 9×10 −3 moles B 9×10 −2 moles C zero D 3×10 −3 moles Medium Solution Verified by Toppr Correct option is A) 32g of O 2=1mol=6.023×10 23 molecules ∴320mg=0.32g=0.01mol=6.023×10 21 From this 6.023×10 20 moles are removed= …
WebOct 26, 2014 · From 200 mg CO2, 10 21 molecules are removed. How many grams of CO2 are left? (A) 0.5 g (B) 0.25 g (C) 0.126 g (D) 0.63 g how_to_reg Follow thumb_up Like (0) visibility Views (6K) edit Answer question_answer Answers (1) person Swathi Ambati Molar mass of CO2 is 44g 44g of CO2 Contains 6.023X1023 molecules 200mg = 0.2 g a dehydratorWebClick here👆to get an answer to your question ️ When x molecules are removed from from 200 mg of N2O , 2.89 × 10^-3 moles of N2O are left. x will be: adeilson da silvaWebMay 10, 2024 · Dear student. 1 mole of CO 2 = 44g contains 6.022 x 10 23 molecules. Thus 200 mg will contain: 0. 2 44 x 6. 022 x 10 23 = 2. 7 x 10 21 molecules. After … adeimf loginWebApr 5, 2024 · Therefore, option D is the correct answer and when $x$ molecules are removed from 200 mg of$ {N_2}O$ moles of $ {N_2}O$ left will be $ {10^ {21}}$ molecules. Note: - In this question we saw the whole question was based on simple calculation but the values are very important. adei logoWebFrom 200 mg of C O 2, 10 21 molecules are removed. How many moles of C O 2 are left? Q. From 392 mg of H2SO4 , 1.204 *10^21 molecules are removed. How many moles are left ? Q. If 3.01 × 10 20 molecules are removed from 98 mg of H 2 S O 4, then the number of moles of H 2 S O 4 left are: j-mail ログインjmam dx早わかりWebFrom `200 mg` of `CO_(2), 10^(21)` molecules are removed. How many grams and moles of `CO_(2)` are left. AboutPressCopyrightContact … jmaixhとは